P(x)=6x^3+11x^2-4x-4. I don't get how you are suppose to do it I know the equation is factors of a subscript o divided by factors a subscript n??
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6x^3+11x^2-4x-4 = (3x-2)(2x^2 + 5x+2) = (3x-2)(x+2)(2x+1)
Let be p divisors of 4 i.e. 1,2,4
and q divisors of 6 are 1,2,3,6
You must try any ±p/q
Let be p divisors of 4 i.e. 1,2,4
and q divisors of 6 are 1,2,3,6
You must try any ±p/q
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Well, you didn't say solve it (above). You said find the POSSIBLE rational roots.
Use the Rational Root Theorem which gives possible roots as:
p/q = +/- 1, 1/2, 1/3, 1/6, 2, 2/3, 4, 4/3
Have a good day!
Use the Rational Root Theorem which gives possible roots as:
p/q = +/- 1, 1/2, 1/3, 1/6, 2, 2/3, 4, 4/3
Have a good day!