1.) Calculate the reaction enthalpy for the reaction....
CH4 (g) + 2O2(g) ---> CO2(g) + 2H2O (l)
Use the series of reactions that follow:
1. C(s) + 2H2(g) --> CH4(g) Delta H= -74.8 kJ
2. C(s) + O2(g) ---> CO2(g) Delta H= -393.5 kJ
3. 2H2(g) + O2(g) ---> 2H2O(g) Delta H= - 484.0 kJ
4. H2O(l) ---> H2O(g) Delta H= 44.0 kJ
CH4 (g) + 2O2(g) ---> CO2(g) + 2H2O (l)
Use the series of reactions that follow:
1. C(s) + 2H2(g) --> CH4(g) Delta H= -74.8 kJ
2. C(s) + O2(g) ---> CO2(g) Delta H= -393.5 kJ
3. 2H2(g) + O2(g) ---> 2H2O(g) Delta H= - 484.0 kJ
4. H2O(l) ---> H2O(g) Delta H= 44.0 kJ
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It is a little hard to explain step-by-step what to do so I hope you can follow what to do by looking at how I arranged the equations.
2 H2O(g) --------------------------> 2 H2O(l) -88
2 H2 + O2 ----------------------------> 2 H2O(g) -484
C + O2 ----------------------------> CO2 -393.5
CH4 -------------------------------> C + 2 H2 + 74.8
________________________________________…
CH4 + 2 O2 ---------------------> CO2 + 2 H2O -890.6 kJ
Once you cancel out the substances that appear BOTH on the left AND the right of the arrows you are left with your net equation.
Hope that helps.
2 H2O(g) --------------------------> 2 H2O(l) -88
2 H2 + O2 ----------------------------> 2 H2O(g) -484
C + O2 ----------------------------> CO2 -393.5
CH4 -------------------------------> C + 2 H2 + 74.8
________________________________________…
CH4 + 2 O2 ---------------------> CO2 + 2 H2O -890.6 kJ
Once you cancel out the substances that appear BOTH on the left AND the right of the arrows you are left with your net equation.
Hope that helps.