i need to know the answer and how to do it cause im stumped
-
total mass of mole of compound = 3 (12 g) + 8 (1 g) + 1 ( 16 g) = 60 g
percent mass of carbon in compound = 3 (12 g) / 60 g = 60%
60% * 24 g = 14.4 g of carbon
percent mass of carbon in compound = 3 (12 g) / 60 g = 60%
60% * 24 g = 14.4 g of carbon