The answers are (0,1) for a max and (1/6, sqrt3/2) for a minimum but I dont know how to reach those answers....help please!!
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maxima and minima occur at zeroes of the first derivative
dy/dx = -pi*sin(pi*x)
at x = 0, dy/dx = -pi*sin(0) = 0
where else might dy/dx = 0? well sin(pi*x) must equal 0. The 0's of sin x occur at 0, pi,2pi,...
although not a maximum in the true sense, 1/6 is the maximum within the range given.
since sine increases monotonically from 0 to pi/2.
dy/dx = -pi*sin(pi*x)
at x = 0, dy/dx = -pi*sin(0) = 0
where else might dy/dx = 0? well sin(pi*x) must equal 0. The 0's of sin x occur at 0, pi,2pi,...
although not a maximum in the true sense, 1/6 is the maximum within the range given.
since sine increases monotonically from 0 to pi/2.