Math geometry easy question!
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Math geometry easy question!

[From: ] [author: ] [Date: 11-10-22] [Hit: ]
What is the measure of angle DBC?The answer is somehow 95-Let the intersection of the two diagonal lines be x. (Im not incorporating the degrees sign.BCA is 25, and DCX is an isosceles triangle--> so,Thus,......
In isosceles trapezoid ABCD, AB is parallel to DC. There are two diagnols that are in the trapezoid that intersect going from angle A to angle C and angle B to angle D. Angle BDC measures 25 degrees, and angle BCA measures 35 degrees. What is the measure of angle DBC?

The answer is somehow 95

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Let the intersection of the two diagonal lines be x. (I'm not incorporating the degrees sign.)

BCA is 25, and DCX is an isosceles triangle--> so, ACD is also 25

Thus,
DBC = 180 - 25 - (25 + 35)
DBC = 95

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Since ΔABC is congruent to ΔBCD, corresponding angles are equal.

Thus ∠DBC = ∠BCA = 35º
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