i dont know who to find t!
50.30 = 11.80t + 9.81t^2
50.30 = 11.80t + 9.81t^2
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9.81t² + 11.80t - 50.30 = 0
a t² + b t + c
Quadratic Formula:
t = [-b ± √(b² - 4ac)]/(2a)
a t² + b t + c
Quadratic Formula:
t = [-b ± √(b² - 4ac)]/(2a)
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Put it all in a standard form.
50.30 = 11.80t + 9.81t^2
9.81t^2 + 11.80t - 50.30=0
and now just use the quadratic formula to find the roots.
50.30 = 11.80t + 9.81t^2
9.81t^2 + 11.80t - 50.30=0
and now just use the quadratic formula to find the roots.
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you have to conver to T^2 +t-number format
9.91t^2 +11.80 t -50.30 =0
looks like you need the
Quadratic Formula:
T = [-b ± √(b² - 4ac)]/(2a)
9.91t^2 +11.80 t -50.30 =0
looks like you need the
Quadratic Formula:
T = [-b ± √(b² - 4ac)]/(2a)
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Do you have access to a graphing calculator? If so... enter
y= 9.81x^2 + 11.8x - 50.3
and your x-intercepts are the solutions/roots.
There are several other ways, but this is the simplest.
y= 9.81x^2 + 11.8x - 50.3
and your x-intercepts are the solutions/roots.
There are several other ways, but this is the simplest.