If a heterozygote for the allele for Huntington's had children with someone who was

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If a heterozygote for the allele for Huntington's had children with someone who was

[From: ] [author: ] [Date: 11-10-22] [Hit: ]

-Simple punnett square here.Therefore 50%. You could simplify the square futher by only using one line for the recessive person as the results would be the same.-50%.The heterozygote is Hh, and the homozygote is hh.......

homozygous recessive, what would be the expected percentage of offspring that will get Huntington's disease?

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Simple punnett square here.
H h
h Hh hh
h Hh hh

Therefore 50%. You could simplify the square futher by only using one line for the recessive person as the results would be the same.

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50%. The heterozygote is Hh, and the homozygote is hh. The Punnett square is:
_____h____
H___Hh____←50% have Huntington's
h___hh____←50% do not

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