Please solve 3x -2x^2 + 9=0

3x -2x^2 + 9=0
-2x^2 + 3x + 9 = 0
2x^2 -3x - 9 =0
2x^2-6x+3x-9=0
2x[x-3]+3[x-3]=0
(2x+3) (x-3)=0
X=3, X=- 3\2

i hope it helps. gud luck fren.

3x -2x^2 + 9=0 First rearrange this mess to match what you are used to.
0 = 2x^2 - 3x - 9 Now look for the factors of -18x^2 that will subtract to give us -3x. try -6 & 3
0 = 2x^2 - 6x + 3x - 9 Now factor by grouping.
0 = (2x^2 - 6x) + (3x - 9 ) Look to see what you can take out of each ().
0 = 2x( x - 3) + 3( x - 3) Notice that each () are the same.
0 = (x - 3) (2x + 3) Now that is factored. therefore...
x - 3 = 0 and 2x + 3 = 0 The rest is yours. R

3x - 2x^2 + 9 = 0
--> 2x^2 - 3x - 9 = 0
--> (x - 3)(2x + 3) = 0
--> x = 3 or x = -3/2