I am clueless of this problem except sin 2x = 2sinx.cosx, but how to continue?
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Since sin x - cos x = p, squaring both sides yields
(sin x - cos x)^2 = p^2
==> sin^2(x) + cos^2(x) - 2 sin x cos x = p^2
==> 1 - sin(2x) = p^2
==> sin(2x) = 1 - p^2.
I hope this helps!
(sin x - cos x)^2 = p^2
==> sin^2(x) + cos^2(x) - 2 sin x cos x = p^2
==> 1 - sin(2x) = p^2
==> sin(2x) = 1 - p^2.
I hope this helps!