Help with 3 Algebra questions:)

1) A Coffee table has a length which is three times its width,and a perimeter of 12ft.Describe this situation as a system of two equations using the variables L=length and W=width. Show your work.

2) Give the solution set of the following systems of equations by any method. Give the name of the method used. Show your work. 3y=6x-12 3y+x=2

3)Solve the following system of equations by graphing it. Label the points you use to make the graph. y-x=1 y+x=1

1) L = 3W
L+W = 6

2)
3y=6x-12
3y+x=2 subtract equations
x = -6x+14
x=2
y=0
Method = elimination

3)
y-x=1
y+x=1 add equations
2y = 2
y = 1
x = 0
Point of intersection (0,1)
so the lines on your graph should intersect at (0,1)

im only going to do one of them for you because i don't wan't to do your work for you, maybe you can learn by me showing you the steps of one of them. I would do the the other 2 problems but i think ur smart enough to do them ur self. You need to try instead of just having someone do it for you. no offense but if you don't do it yourself ur gonna fail ur math tests.

i'll do the first one.
1) what you know: a coffee table.
L (length) 3xW
perimeter= 12ft

so ur equations would be: 12=2L + 2W (because perimeter means adding the sides up and so 2 lengths and 2 widths.)
ur 2nd equation would be: L= 3W (to figure out the width to plug into ur 1st equation to get you answer.


anyways hope i helped if not sorry.

Its just hard i tried it sorry i cant