Plan coordinate geometry help ~

Determine the x- and y-intercepts and the slope of the given lines, and sketch their graphs.
(c) √2 x - √3 y = 2

I know how to find the slope from equation but this equation contain √ so I have stuck....so....and also what does the sketch graph mean? Does it means draw out the x and y axis in graph after I find?
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Find equations for the lines through P that are (i) parallel to, and (ii) perpendicular to the given line.
(a) P(2,1), 2x+y=4

Also if you don't mind pls teach me this question also pls ~ I have no idea how to do this....very thanks you ~

[ c ]

L : √2. x - √3. y = 2 .............. (1)

y = 0 gives : √2.x = 2

i.e., x-int. = 2/√2 = √2.
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x = 0 gives : -√3.y = 2

i.e., y-int. = -2/√3.
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slope = - ( coeff. of x ) / ( coeff. of y )

. . . . = -(√2)/(-√3)

. . . . = √(2/3)
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[ a ]

Line thru P(2,1) and

(i) parallel to 2x + 1y = 4 is : 2(x-2) + 1(y-1) = 0, i.e., 2x + y = 5

(ii) perp. to 2x + 1y = 4 is : 1(x-2) - 2(y-1) = 0, i.e., x - 2y = 0.
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Happy To Help !
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