when 7.08 grams of CaO(s) is completely dissolcved by HBr(aq), how many grams of CaBr2 are formed in solution?
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CaO + 2HBr --> CaBr2 + H2O
7.08g CaO / 56g/mole = 0.126moles
1:1 ratio of CaO:CaBr2
0.126moles CaBr2 produced x 200g/mole = 25.28g CaBr2 produced
7.08g CaO / 56g/mole = 0.126moles
1:1 ratio of CaO:CaBr2
0.126moles CaBr2 produced x 200g/mole = 25.28g CaBr2 produced