Please n thanks <3
1) What is the formula for Magnesium acetate?
2) Write a balanced equation for the following reaction: Iron + fluorine -----> iron (III) fluoride
3) Using the equation from #2 determine the number of grams of iron (III) fluoride produced from the reaction of 2.5 grams of iron.?
and the number of 25 grams of iron?
1) What is the formula for Magnesium acetate?
2) Write a balanced equation for the following reaction: Iron + fluorine -----> iron (III) fluoride
3) Using the equation from #2 determine the number of grams of iron (III) fluoride produced from the reaction of 2.5 grams of iron.?
and the number of 25 grams of iron?
-
1. (CH3COO)2Mg
2. 2Fe + 3F2 = 2FeF3.
3. 2.5g of Fe = 2.5/56 = 0.045mole of Fe and this will produce 0.045mole of FeF3 = 0.045 x 113 = 5.085g of FeF3.
25g of Fe = 25/56 = 0.45mole of Fe and this will produce 0.45mole of FeF3 = 0.45 x 113 = 50.85g of FeF3.
2. 2Fe + 3F2 = 2FeF3.
3. 2.5g of Fe = 2.5/56 = 0.045mole of Fe and this will produce 0.045mole of FeF3 = 0.045 x 113 = 5.085g of FeF3.
25g of Fe = 25/56 = 0.45mole of Fe and this will produce 0.45mole of FeF3 = 0.45 x 113 = 50.85g of FeF3.
-
1) What is the formula for Magnesium acetate?
Mg(CH3COO)2
2) Write a balanced equation for the following reaction: Iron + fluorine -----> iron (III) fluoride
2Fe + 3F2 --> 2FeF3
3) Using the equation from #2 determine the number of grams of iron (III) fluoride produced from the reaction of 2.5 grams of iron.?
2.5g Fe X (1mol Fe/55.85g) X (2mol FeF3/ 2mol Fe)x (112.85g/1mol FeF3)=5.05g
Mg(CH3COO)2
2) Write a balanced equation for the following reaction: Iron + fluorine -----> iron (III) fluoride
2Fe + 3F2 --> 2FeF3
3) Using the equation from #2 determine the number of grams of iron (III) fluoride produced from the reaction of 2.5 grams of iron.?
2.5g Fe X (1mol Fe/55.85g) X (2mol FeF3/ 2mol Fe)x (112.85g/1mol FeF3)=5.05g
-
1) Mg(CH3COO)2
2.5 g X g
2) 2Fe + 3F2 -> 2FeF3
112 g/mol 226 g/mol
X = 2.5 g * 226 g/mol / 112 g/mol = 5.045 g
25g * 226 g/mol / 112 g/mol = 50.45 g
2.5 g X g
2) 2Fe + 3F2 -> 2FeF3
112 g/mol 226 g/mol
X = 2.5 g * 226 g/mol / 112 g/mol = 5.045 g
25g * 226 g/mol / 112 g/mol = 50.45 g