Anyone good at CHEMISTRY equations and formulas? 5STARS 10pts
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Anyone good at CHEMISTRY equations and formulas? 5STARS 10pts

[From: ] [author: ] [Date: 11-05-08] [Hit: ]
085g of FeF3.25g of Fe = 25/56 = 0.45mole of Fe and this will produce 0.45mole of FeF3 = 0.45 x 113 = 50.85g of FeF3.......
Please n thanks <3
1) What is the formula for Magnesium acetate?


2) Write a balanced equation for the following reaction: Iron + fluorine -----> iron (III) fluoride



3) Using the equation from #2 determine the number of grams of iron (III) fluoride produced from the reaction of 2.5 grams of iron.?
and the number of 25 grams of iron?

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1. (CH3COO)2Mg
2. 2Fe + 3F2 = 2FeF3.
3. 2.5g of Fe = 2.5/56 = 0.045mole of Fe and this will produce 0.045mole of FeF3 = 0.045 x 113 = 5.085g of FeF3.
25g of Fe = 25/56 = 0.45mole of Fe and this will produce 0.45mole of FeF3 = 0.45 x 113 = 50.85g of FeF3.

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1) What is the formula for Magnesium acetate?
Mg(CH3COO)2

2) Write a balanced equation for the following reaction: Iron + fluorine -----> iron (III) fluoride

2Fe + 3F2 --> 2FeF3

3) Using the equation from #2 determine the number of grams of iron (III) fluoride produced from the reaction of 2.5 grams of iron.?

2.5g Fe X (1mol Fe/55.85g) X (2mol FeF3/ 2mol Fe)x (112.85g/1mol FeF3)=5.05g

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1) Mg(CH3COO)2

2.5 g X g
2) 2Fe + 3F2 -> 2FeF3
112 g/mol 226 g/mol

X = 2.5 g * 226 g/mol / 112 g/mol = 5.045 g

25g * 226 g/mol / 112 g/mol = 50.45 g
1
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