magnesium metal reacts with hydrochloric acid to form aqueous magnesium chloride and hydrogen gas. An excess of magnesium is reacted with 20.0 mL of 3.00 M hydrochloric acid, and all of the hydrogen is collected in a balloon at 25 C and 1.00 atm. what is the expected volume of the balloon?
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Mg + 2HCl ----> MgCl2 + H2
moles of hydrochloric acid used = 0.06
but 2 mole HCl gives 1 mole H2
so 0.06 mole HCl gives 0.03 mole H2
use PV= nRT to get the volume of the balloon
so V = 0.734 L
moles of hydrochloric acid used = 0.06
but 2 mole HCl gives 1 mole H2
so 0.06 mole HCl gives 0.03 mole H2
use PV= nRT to get the volume of the balloon
so V = 0.734 L