We have :
Leap Year = 366 days = ( 52 Weeks ) + ( 2 Days ).
Thus we already have 52 Mondays and 52 Wednesdays.
Those surplus 2 days can be :
(1) Mon-Tues
(2) Tues-Wed
(3) Wed-Thurs
(4) Thurs-Fri
(5) Fri-Sat
(6) Sat-Sun
(7) Sun-Mon.
The possibilities (4), (5) and (6) do not contribute
any additional Monday or Wednesday.
Hence, the required probability is
= ( no. of favourable cases ) / ( total no. of cases )
= 3/7 ........................................… Ans.
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Happy To Help !
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Leap Year = 366 days = ( 52 Weeks ) + ( 2 Days ).
Thus we already have 52 Mondays and 52 Wednesdays.
Those surplus 2 days can be :
(1) Mon-Tues
(2) Tues-Wed
(3) Wed-Thurs
(4) Thurs-Fri
(5) Fri-Sat
(6) Sat-Sun
(7) Sun-Mon.
The possibilities (4), (5) and (6) do not contribute
any additional Monday or Wednesday.
Hence, the required probability is
= ( no. of favourable cases ) / ( total no. of cases )
= 3/7 ........................................… Ans.
____________________________
Happy To Help !
____________________________
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You are Welcome, Sunny K !
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