HOME > Chemistry > How many moles of helium occupy a volume of 5.00 L at 227.0°C and 5.00 atm? (R = 0.0821 atm.L/mol.K)
How many moles of helium occupy a volume of 5.00 L at 227.0°C and 5.00 atm? (R = 0.0821 atm.L/mol.K)
[From: ][author: ][Date: 11-04-23][Hit: ]
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PV = nRT so n = PV/RT
n = (5 x 5)/(0.0821 x 500.15)
= 25/41.062315
= 0.61 (to two decimal places)
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