(co(h2o)6)^2+
co2(so4)3
(cocl4)^2-
i have the answers ..
2+
3+
and 2+
can you explain for each how to get it?? step by step plz.
co2(so4)3
(cocl4)^2-
i have the answers ..
2+
3+
and 2+
can you explain for each how to get it?? step by step plz.
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First H2O is neutal ligand, so whatever the charge on the complex that will be the oxidation state of the central metal. So in this example Co is in +2 oxidation state.
In cobaltsulphate cobalt is in +3 oxidation state. Sulphat ion has -2 charge on it and there are three sulphate ions so to neutralise that there must be +6 charge contributed by two cobalt ions. So each cobalt is in +3 oxidation state.
In the third complex Cl is uni negetively charged ligand, so there are four such chlorine ligands and charge on the coples is 2-.
so suppose the oxidation state ( charge on the atom) of cobalt is 'x' , the charge on the Cl is -1 (stadard, all the halogens will be in -1 oxidation state when they act as ligands).
charge on metal + (charge on the ligand) no.of ligands = charge on the complex
x + (-1) 4 + -2 , if u caleculate according to this you will get 'x' value as +2.
In cobaltsulphate cobalt is in +3 oxidation state. Sulphat ion has -2 charge on it and there are three sulphate ions so to neutralise that there must be +6 charge contributed by two cobalt ions. So each cobalt is in +3 oxidation state.
In the third complex Cl is uni negetively charged ligand, so there are four such chlorine ligands and charge on the coples is 2-.
so suppose the oxidation state ( charge on the atom) of cobalt is 'x' , the charge on the Cl is -1 (stadard, all the halogens will be in -1 oxidation state when they act as ligands).
charge on metal + (charge on the ligand) no.of ligands = charge on the complex
x + (-1) 4 + -2 , if u caleculate according to this you will get 'x' value as +2.
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[Co(H2O)6]^2+
As aquo(water) is neutral ligand and have no charge so the oxidation number of cobalt is +2 and these electrons has been ionized from 4S orbital.
In 2nd compound the oxidation number of cobalt is +3 because SO4 has -2 charge so -2*3 sulfat group holding -6 oxidation so to neutralize the 3 sulfat groups there are 2 cobalt atoms and have each has +3 oxidation state.
the last one complex! Cobalt has +2 oxidation state because 4 chlorides having -4 charge and the whole complex have -2 charge which means that the oxidation number of cobalt is +2
(cocl4)^2-
co -1*4= -2
co -4 = -2
co = -2+4
co= +2...
pay thanx on +923459064909
As aquo(water) is neutral ligand and have no charge so the oxidation number of cobalt is +2 and these electrons has been ionized from 4S orbital.
In 2nd compound the oxidation number of cobalt is +3 because SO4 has -2 charge so -2*3 sulfat group holding -6 oxidation so to neutralize the 3 sulfat groups there are 2 cobalt atoms and have each has +3 oxidation state.
the last one complex! Cobalt has +2 oxidation state because 4 chlorides having -4 charge and the whole complex have -2 charge which means that the oxidation number of cobalt is +2
(cocl4)^2-
co -1*4= -2
co -4 = -2
co = -2+4
co= +2...
pay thanx on +923459064909