1) What volume of a 10 mol/L H2SO4 solution is needed to make 1 L of 1.0 mol/L solution of H2SO4?
Thanks :P
Thanks :P
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Your final solution contains n(H2SO4) =1.0 mol/L * 1 L = 1.0 mol of sulfuric acid which is exsactly the amount of acid that was taken from your stock solution (10 mol/L).
V(H2SO4) = 1.0 mol/ 10 mol/L = 0.1 L or 100 ml
To make it even simpler: it's a 1 to 10 dilution, which means the final solution is 10 times less concentrated, so you will need a tenth part of you final solution volume (1L) to make a 1/10 dilution, and 1/10 of 1 L is 100ml :)
V(H2SO4) = 1.0 mol/ 10 mol/L = 0.1 L or 100 ml
To make it even simpler: it's a 1 to 10 dilution, which means the final solution is 10 times less concentrated, so you will need a tenth part of you final solution volume (1L) to make a 1/10 dilution, and 1/10 of 1 L is 100ml :)
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you're welcome :)
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