The heat dissipated by the 4 ohm resistor in 5s will be
5J
10J
20J
30 J
Please explain me with the formula..
5J
10J
20J
30 J
Please explain me with the formula..
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Hello,
I = V/R = 6/(4+2) = 1 Amp.
P = (I^2) * R = (1^2) * 4 = 4 W
Energy = Power * Time = 4 * 5sec = 20 Ws... = 20 J............
I = V/R = 6/(4+2) = 1 Amp.
P = (I^2) * R = (1^2) * 4 = 4 W
Energy = Power * Time = 4 * 5sec = 20 Ws... = 20 J............
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2Ω+4Ω= 6Ω
6V/6Ω = 1A
P = i²*R = 1²*4Ω = 4W = 4J/s => 4J/s * 5s = 20 J
6V/6Ω = 1A
P = i²*R = 1²*4Ω = 4W = 4J/s => 4J/s * 5s = 20 J