Find y if the line through (4, 2) and (5, y) has a slope of 6.
How do you solve this?
How do you solve this?
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y - 2 = 6(x - 4)
y - 2 = 6x - 24
y = 6x - 22
Substitute 5 for x and solve for y.
y = 6(5) - 22 = 8
y - 2 = 6x - 24
y = 6x - 22
Substitute 5 for x and solve for y.
y = 6(5) - 22 = 8
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(y₂−y₁)/(x₂−x₁) = 6
(y−2)/(5−4) = 6
(y−2)/1 = 6
y − 2 = 6
y = 8
(y−2)/(5−4) = 6
(y−2)/1 = 6
y − 2 = 6
y = 8
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(y-2)/(5-4)=6
(y-2)/1=6
y-2=6
y=8
(y-2)/1=6
y-2=6
y=8
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calculate the slope:
...........2 - y
m = ----------- = 6
...........4 - 5
...........2 - y
m = ----------- = 6...........Now cross multiply
.............-1
2-y = -6..........................Now solve for y
y = 8...............................ANS
...........2 - y
m = ----------- = 6
...........4 - 5
...........2 - y
m = ----------- = 6...........Now cross multiply
.............-1
2-y = -6..........................Now solve for y
y = 8...............................ANS