How many grams of NaCl are needed to make 1.00 liter of a 3.00 M NaCl solution?

Well first we need to find moles of NaCl

Molar concentration = #moles/Volume (L)
3.00M = #moles / 1.00L
Cross multiply
#moles = 3.00moles

Now we use mole equaton

#moles= mass (g) / Molar mass (g/mol)
3. 00 mol = mass (g) / 58.44 g/mol
mass (g) = 175.32 grams.

3 M means 3 moles / L

You have 1 L of solution, how many moles of NaCl do you need? What is the mass of that number of moles of NaCl?