Physics......electrostatic force
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Physics......electrostatic force

[From: ] [author: ] [Date: 12-08-27] [Hit: ]
F= (9x10^9 N*m^2/C^2) (+1.8 * 10-8 C)(+1.5 * 10-8 C) /0.F = .......
There are two balls. Ball A has a charge of +1.8 * 10-8 C and Ball B has a charge of
+1.5 * 10-8 C and is 0.002 m away from A.

a. What is the force acting on A?

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F = q1*q2/4pi(epsilon) r^2

1/4pi(epsilon) = 9x10^9 N*m^2/C^2

F= (9x10^9 N*m^2/C^2) (+1.8 * 10-8 C)(+1.5 * 10-8 C) / 0.002^2

F = .6075 N

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use coulomb force
1
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