f(x) = x + 1/x^2 - 8x + 7
I know its 1,7 but I have no idea how they got that. can someone help?-Vertical asymptotes will occur when the denominator equals zero when the numerator doesnt.
By setting
Find the standard form of the equation of the parabola with the given characteristics. Vertex: (8, -5); focus: (8, -3)
thanks-Since the vertex is lower on the y axis than the focus, and x is the sa
does the x in front of the parenthesis always = 0 or do you distribute first. Thanks for any help.-The x in front wont always equal 0 but it can. What the equation x(x-1)=0 is saying is that x = 0 and
Another question I am having major trouble with. I have no idea how to do it. If you guys could help me, it would be much appreciated.-There are all kinds of equivalent expressions. I dont see that an
G = 4F2 (SQUARED) -3
G+ 11F = 0
(4F2 - 3) + 11F =0
4F2 - 3 + 11F = 0
I DONT KNOW HOW TO FACTORISE THIS, IS IT POSSIBLE? AM I WRONG?-I DONT KNOW HOW TO FACTORISE THIS
You can always use the quadrat
How do I differentiate y = arccos (1-2x^2) with respect to x (with a simplified answer too)?
Detailed steps would be most appreciated.-F.Y.I arccosine is inverse cosine----cos^-1 u
so i have this eq
Given that y is inversely proportional to x2 (X squared), and that y=2 when x=5.
a) Find an expression for y in terms of x
b) calculatei) the value of y when x=2
ii) a value of x when y=0.5
Thanks :)
it looks like this......
http://www.flickr.com/photos/62069060@N02/5650497812/in/photostream
find the measurment of angle A-Not enough information without additional assumptions.
I will assume that
So, I know the question sounds a bit confusing?
Let me give an example...
8 is a multiple of 4
4 is a multiple of 2
So why must 8 also be a multiple of 2?
I know this is a simple topic and I underst
Could someone explain to me what a logarithm is? What Im reading in my material, is when the function grows etc. which is no help at all.
Lets say we have something like this:
y=log(subscript)2 x, ho
complete the square to form a perfect square trinomial x squared+5x+_______-(5/2)² = 25 / 4
We are basically looking for b² as in
(a + b)² = a² = 2ab + b²
a² = x², so a= x
2ab = 2(x)(b) = 5x
2b =
recall that integral (ln x)dx = x lnx - x + C
find the area of the region in the first quadrant bounded by the graph of y = lnx, the line tangent to y=ln x at x = 3, and the x- and y-axes.-Hello
y(3)
I was thinking about taking cal 3 and physics 2 together during the summer, but if linear algebra isnt too hard, i might just hold physics off til fall semester-I took linear alg in first term of univ