I DONT UNDERSTAND THE DAMN QUESTION HOW AM I CHEATING IF IM PRACTICING IN THE SUMMER TIME? IF YOU WANNA BE RUDE THEN BUZZ OFF..
The polynomail 6x^3 + mx^2 + nx -5 has a factor of x+1. When divided by
We know that 2/10 = 0.2
But, Can you Prove
that 2/10 = 2
Other Students : cha cha Yeppadi paa mudiyum.? Engineering Terrors :
ha ha yevvallavo pannittoam idha panna maattoamaa.?
2 – Two, 10 – Ten..
Tw
How do you find the gradient of the tangent to the curve y= x^2+ 5x+ 6 at the point (1,12)?-Differentiate the given curve:
so,
dy/dx = 2x + 5
Now since the point (1,12) its x co-ord is 1
So put this
34 is a composite number; it has factors other than 1 and itself. It is not a prime number.
The 4 factors of 34 are 1, 2, 17, and 34.
The factor pairs of 34 are 1 x 34 and 2 x 17.
The proper fac
No, the equation is represented by a horizontal line through 10 on the y-axis.An asymptote is a line the graph approaches but never reaches.-NO , because for any x going to infinity , f(x) doesn´t ten
sin(pi/4+x)-cos(pi/4+x)
So far I have: =(sinpi/4)(cosx)-(cospi/4)(cosx)=(sqrt2/2)(cosx)-(sqrt2/2)(cosx)
...and now Im stuck :/
The answer is suppossed to be sqrt2sinx-I can see your problem already...
Having some issues figuring out how to do this problem, it is 1 over x times the square root of one minus ln x squared all multiplied by dx.-Use the substitution u = ln x, du = (1/x) dx.
So, ∫ dx / [
Jimmy drove to his cabin on the lake and back. It took 0.6 hours longer to go there than it did to come back. The average speed on the trip there was 46 km/h. The average speed on the way back was 52
How do I solve this system of equations with substituion?
9x+10y=90
2x-8y=16
And can you please explain how to do it? I dont really get it
Thx.-9x+10y=90
2x-8y=16
9*x + 10*y = 90
x - 4*y = 8
x
solution pls...-Factor the bottom(x+1)/(x+4)(x+1) there is a removable disconunity at x=-1 and an unremovable disconutity at x=-4
(-infin,-4)U(-4,-1)U(-1,infin)-YOUR MOTHER DOES MATHS!
The graph y=kx+3 is tangent to the circle x^2 + y^2 = 7.
Find the possible values of k.-x^2 + (kx + 3)^2 = 7
x^2 + k^2 * x^2 + 6kx + 9 = 7
x^2 * (1 + k^2) + 6kx + 2 = 0
In order for this line to be