Maths Question- Please Help ASAP!!!
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Maths Question- Please Help ASAP!!!

[From: ] [author: ] [Date: 11-08-09] [Hit: ]
Now since the point (1,When x=1,http://www.imagup.com/data/1127540530.Bye !......
How do you find the gradient of the tangent to the curve y= x^2+ 5x+ 6 at the point (1,12)?

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Differentiate the given curve:
so,

dy/dx = 2x + 5

Now since the point (1,12) its x co-ord is 1
So put this in the dy/dx equation and value of slope would be 7

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Hello

The gradient ( or slope) of the tangent to a curve at a point is the value of the derivative at that point

Derivative : 2x+5

When x=1, the derivative is 2(1) + 5 = 7

Now look at the graph :

http://www.imagup.com/data/1127540530.ht…

Hope it helped

Bye !
1
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