Having some issues figuring out how to do this problem, it is 1 over x times the square root of one minus ln x squared all multiplied by dx.
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Use the substitution u = ln x, du = (1/x) dx.
So, ∫ dx / [x √(1 - (ln x)²)]
= ∫ du / √(1 - u²)
= arcsin u + C
= arcsin(ln x) + C.
I hope this helps!
So, ∫ dx / [x √(1 - (ln x)²)]
= ∫ du / √(1 - u²)
= arcsin u + C
= arcsin(ln x) + C.
I hope this helps!
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kb answer is perfect