I DONT UNDERSTAND THE DAMN QUESTION HOW AM I CHEATING IF IM PRACTICING IN THE SUMMER TIME? IF YOU WANNA BE RUDE THEN BUZZ OFF..
The polynomail 6x^3 + mx^2 + nx -5 has a factor of x+1. When divided by x-1, the remainder is -4. What are values of m & n?
The polynomail 6x^3 + mx^2 + nx -5 has a factor of x+1. When divided by x-1, the remainder is -4. What are values of m & n?
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Wow! I will try to help:)
when we find factors, we find zeroes. Since x +1 is a factor, then f(-1)= 0
If f(1) = 0, then (x-1) would be a factor. But it is not.
If the remainder is -4 then the remainder theorem says that f(1) = -4
6x^3+mx^2+nx-5
Plug in 1 for x: 6+ m + n -5= -4
Plug in -1 for x: -6 + m - n-5= 0
Now simplify:
m + n= -5
m - n = 11
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2m= 6
m=3
n = -8
:) R
when we find factors, we find zeroes. Since x +1 is a factor, then f(-1)= 0
If f(1) = 0, then (x-1) would be a factor. But it is not.
If the remainder is -4 then the remainder theorem says that f(1) = -4
6x^3+mx^2+nx-5
Plug in 1 for x: 6+ m + n -5= -4
Plug in -1 for x: -6 + m - n-5= 0
Now simplify:
m + n= -5
m - n = 11
-------------
2m= 6
m=3
n = -8
:) R
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If x+1 is a factor, x= -1 is a solution, when you substitute x = -1 in the equation it will = 0
6(-1)^3 + m(-1)^2 + n(-1) - 5 = 0
-6 + m - n - 5 = 0
m - n = 11
If x-1 leaves a remainder of -4 then if you substitute x = 1 into the equation it will = -4
6(1)^3 + m(1)^2 + n(1) - 5 = -4
6 + m + n - 5 = -4
m + n = -5
now you have solve the simultanious equations
I got m = 3 and n = - 8
6(-1)^3 + m(-1)^2 + n(-1) - 5 = 0
-6 + m - n - 5 = 0
m - n = 11
If x-1 leaves a remainder of -4 then if you substitute x = 1 into the equation it will = -4
6(1)^3 + m(1)^2 + n(1) - 5 = -4
6 + m + n - 5 = -4
m + n = -5
now you have solve the simultanious equations
I got m = 3 and n = - 8