im so confused with zero and negative exponent please answer all and help me please please !!!!!
1) 8p^-5 q^0 r^6/ 16p q^2 r^10
2)36x^10 y^-5/ 12x^-3 y^-7
3) 2^-3 + 4^-1
4) (5^-1 x^-3 y^4)^-2 (x^5 y^
Im working on a short story that involves two different universes I wont go into massive detail but my basic problem is that a new universe is expanding inside another so the outside universe needs to
partial integral !!
Good answer *5-Let I = ∫{xdx/sq rt(4x+1)] put 4x+ 1 = t^2 or 4dx = 2t*dt or dx = t*dt/(2) and x = (t^2 -1)/4 or I = (1/8)∫{t(t^2-1)dt/t] = (1/8)∫(t^2-1)dt] = t^3/24 - t/8 + C = (1/
So if I have a rectangle and one side is 3a and the area is 6a to the second minus 3a thin what would the missing side and perimeter be?
Same thing on this one. If one side is a to the second b to th
I URGENTLY need help with some basic, middle school geometry that involves finding pronumerals. I cannot draw the diagrams here, so please e-mail foxyfreelance@gmail.com if you can help me. I will be
(4th root of 27) / (square root of 3). I rewrite it as 27^(1/4)/3^(1/2)and *then* to (3^3)^(1/4)/3^(1/2) and mess up somewhere around there.
Any help, answers or even hints appreciated, thanks!-Youre
Im trying to find the complex zeros of a polynomial function, x^3-8x^2+25x-26, i have found that x-2 is a factor, but when i use synthetic division, i do not end up with a remainder of zero. What does
https://picasaweb.google.com/lh/photo/QU…
Is the formula given there correct?? Cuz by no way I am getting that formula and moreover in the example theyve given, they treat -(1/x^2) as f(x) not (1/x).
how would i graph this?-Do you have to solve it graphically? If so, pick two points for x, plug them each into this equation, one at a time, and see which two y values you get. For example, if I pick
There are no draws.-1) W = 4L
2) W = L + 6
substitute:
4L = L + 6
3L = 6
L = 6/3 = 2
using eq(2):
W = 2 + 6 = 8
check using eq(1):
8 = 4(2)
8 = 8
They won 8 games out of a total of 10 games.
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can anyone answer these questions with step by step method? thanks alot!!!!!!
1. Find d^2y/dx^2,
y^4 + x + sin(y) = 7
dy/dx =1/(-4*y^3-cos(y))
i tried several ways and didnt get it right, these ans
This problem is confusing me somewhat, so I would really appreciate any help. I know that the final answer is 3x.
(3-x)^2 x + (3-x)x^2
________________x-3
note: in the numerator, on the left hand si
how to intergrate 1/(3+4x)^4. isit using u subtitution, u=3+4x or (3 + 4x)^4-u=3+4x
du=4dx
so
∫ 1/(3 + 4x)^4dx=1/4∫ (1/u^4)du
1/4*∫u^-4du
1/4 *(u^-3)/-3since ∫x^n=(x^n+1)/n+1 provided x not = 1
or
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