Integration by parts
Favorites|Homepage
Subscriptions | sitemap
HOME > Mathematics > Integration by parts

Integration by parts

[From: ] [author: ] [Date: 11-09-18] [Hit: ]
they treat -(1/x^2) as f(x) not (1/x).So please tell me whether the formula is wrong or the example given is wrong or both are wrong.-The formula by itself is correct since [f e^x] = [f + f] e^x.However, in the example, the author mistook f for f.......
https://picasaweb.google.com/lh/photo/QU…

Is the formula given there correct?? Cuz by no way I am getting that formula and moreover in the example they've given, they treat -(1/x^2) as f(x) not (1/x).

So please tell me whether the formula is wrong or the example given is wrong or both are wrong.

-
The formula by itself is correct since [f e^x]' = [f + f'] e^x. However, in the example, the author mistook f' for f. The derivative of 1/x is -1/x^2, not the other way around.

Therefore the result of integral( (x-1)/x e^x dx ) is e^x/x.

-
The formula is correct.
int e^x(f(x)+f'(x))
=> f(x) int e^x-int (f'(x) int e^x)+int e^x f'(x)
=> e^x f(x) [integrating by parts letting u as f(x) and v as e^x.]

-
The formula is correct, but they are using a different method of integration. I forget what it's called but it's definitely not integration by parts.

-
the formula is correct
1
keywords: Integration,by,parts,Integration by parts
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .