The temperature in Potsdam was -12F at 8 AM. The temperature increased 3F every hour. Write an equation to show the temperature at any time during the day. Use that equation and solve it to find the time when it would be 15F.
I know the answer is 5PM but I cant get the equation I tied a couple but they are not correct.
3(x-12)=15
-12(3+x)=15
I know the answer is 5PM but I cant get the equation I tied a couple but they are not correct.
3(x-12)=15
-12(3+x)=15
-
y = -12 + 3x
to solve
15 = -12 + 3x
x = 9 hours
5pm
to solve
15 = -12 + 3x
x = 9 hours
5pm
-
T=3h -36
T= 3(h-12)
h= T/3 + 12
when T = 15
h=17 (which is 24 time for 5pm)
you can also do this problem using implicit differentiation of the rate dt/dh = 3 with initial conditions T=-12 when h=8
T= 3(h-12)
h= T/3 + 12
when T = 15
h=17 (which is 24 time for 5pm)
you can also do this problem using implicit differentiation of the rate dt/dh = 3 with initial conditions T=-12 when h=8
-
T = 3(x - 8) - 12 => at 8 AM x = 8
15 = 3(x - 8) - 12
27 = 3x - 24
51 = 3x
x = 17 i.e. 5 PM
15 = 3(x - 8) - 12
27 = 3x - 24
51 = 3x
x = 17 i.e. 5 PM