The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abbreviation (w/v) is also common.
How many grams of sucrose are needed to make 625 mL of a 39.0% (w/v) sucrose solution?
How many grams of sucrose are needed to make 625 mL of a 39.0% (w/v) sucrose solution?
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"The mass of solute per 100 mL of solution is abbreviated as (m/v)"
So, 39% of 100 is 39 g
39 g of solute in 100 mL of solution is 39% (w/v)
39 is 100 as x is to 625
x = 243.75 g of solute required (round off as you see fit)
So, 39% of 100 is 39 g
39 g of solute in 100 mL of solution is 39% (w/v)
39 is 100 as x is to 625
x = 243.75 g of solute required (round off as you see fit)