Integral 4x^3 - 3x^2 - 38x - 11 from 1 to 5

for best answer?

Integral 4x^3 - 3x^2 - 38x - 11 =
x^4 - x^3 - 19x^2 + C ] 1 to 5
625 - 125 -475 - (1 - 1 - 19) = 44

im not going to write the whole thing out for you because that's your job, but i will tell you how to do it.

the integral of x^n is (x^(n+1))/(n+1)

Also, the integration function is linear, meaning you can break it up into the integral of each part, which makes it fairly easy.

Note that the integral of -11 is just -11x

Hope this helps