Evaluate the indefinate integral
∫-5/((s^2)((s-1)^2))
so the numerator only has a -5 and the denominator has a (s^2)(s-1)^2 if this helps
ok so after i do the whole integration i get
-5(-1/(1-s)-1/s-2ln(1-s)+2ln(s))+C
please i need a lot of help i keep on getting this answer and i have done this sooo many times
∫-5/((s^2)((s-1)^2))
so the numerator only has a -5 and the denominator has a (s^2)(s-1)^2 if this helps
ok so after i do the whole integration i get
-5(-1/(1-s)-1/s-2ln(1-s)+2ln(s))+C
please i need a lot of help i keep on getting this answer and i have done this sooo many times
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int( - 5/(s^2*(s - 1)^2), s) = 5/(s - 1) + 5/s + 10*ln(s - 1) - 10*ln(s) + C
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partial fraction is of form a/s + b/s^2+c/(s-1)+d/(s-1)^2
Ignore the -5 and assume lhs is 1 = a*s*(s-1)^2 + b*(s-1)^2+c*s^2*(s-1)+d*s^2 after clearing fractions:
let s=0 and you get b=1...let s=1 and you get d=1...
equate variables...no s^3 on lhs, rhs has a*s^3+c*s^3...a= - c...if you find one, you find the other.
Just let x be your fave # of the day and you'll get another equation involving a and c (remember you already know what b and d are). Solve this system to get
aln(s)-bs^-1+cln(s-1)-d(s-1)^-1+ constant of integration.
Ignore the -5 and assume lhs is 1 = a*s*(s-1)^2 + b*(s-1)^2+c*s^2*(s-1)+d*s^2 after clearing fractions:
let s=0 and you get b=1...let s=1 and you get d=1...
equate variables...no s^3 on lhs, rhs has a*s^3+c*s^3...a= - c...if you find one, you find the other.
Just let x be your fave # of the day and you'll get another equation involving a and c (remember you already know what b and d are). Solve this system to get
aln(s)-bs^-1+cln(s-1)-d(s-1)^-1+ constant of integration.