How do I solve this (algebra)

w+2/3w+1=41

1.w+2/3w=41-1
2.5w/3=40
3.w=(40X3)\5
4.w=24.

w + 2/3w + 1 = 41
i assume you mean (2/3)w and not 2/(3w)
multiply both sides by 3
3w + 2w + 3 = 123
add teh ws and subtract 3 from both sides
5w = 123 - 3
5w = 120
w = 24

I'm assuming you mean w +(2/3)w +1 = 41

If yes, then subtract 1 from each side; simplify the left
to get (5/3)w; then mult each side by 3/5 to get

w =24

w= 3w/3 (multiplying top and bottom with 3)
using this we get
( 3w+2w ) /3 +1=41
5w/3 + 1=41
5w/3=41-1
5w/3=40
5w= 40*3=120
w=120/5=24
so w=24

w+2/3w+1 = 41
w+2 = 41(3w+1)
w+2 = 123w + 41
w-123w = 41-2
-122w = 39

w=-39/122
w = -0.32 --------Answer

(3w+2w+3)/3=41
=> 5w+3=123
=> 5w=123-3
=> 5w=120
=>w=24