I am having some difficulties with my chemistry homework...Please help ):
H2S08, K2Mn04, HBrO3,CrO2Cl
if possible please explain how you arrive at the answer thanks (:
H2S08, K2Mn04, HBrO3,CrO2Cl
if possible please explain how you arrive at the answer thanks (:
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I always start with oxygen and hydrogen, oxygen is always -2 and hydrogen is always +1. So H2S08, will have -16 from the oxygen and +2 from the hydrogen, giving it an oxidation state of +14, according to the formula you have given. However, that is an impossible oxidation number for sulfur, its highest possible oxidation number is +6, the formula you have given does not exist. The formula for sulfuric acid is H2SO4, which will be the highest allowed number of oxygen atoms with sulfur, giving you an oxidation number of +6 for the sulfur.
K2Mn04: K is always +1 for a total of +2, you get -8 from the O, so the oxidation number of Mn is +6.
HBrO3: +1 from the hydrogen, -6 from the O gives you +5 for the boron
CrO2Cl: This is tricky. You get -4 from the O. Cl is normally -1 but it can have other oxidation numbers, particularly when combined with oxygen. If it is -1, then the Cr would be+5, but this is not an allowed oxidation state for Cr. So the Cl must be +1 and the Cr is then +3.
K2Mn04: K is always +1 for a total of +2, you get -8 from the O, so the oxidation number of Mn is +6.
HBrO3: +1 from the hydrogen, -6 from the O gives you +5 for the boron
CrO2Cl: This is tricky. You get -4 from the O. Cl is normally -1 but it can have other oxidation numbers, particularly when combined with oxygen. If it is -1, then the Cr would be+5, but this is not an allowed oxidation state for Cr. So the Cl must be +1 and the Cr is then +3.