A block on a 30 degree incline has an initial velocity of 3.5 m/s up the incline.
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A block on a 30 degree incline has an initial velocity of 3.5 m/s up the incline.

[From: ] [author: ] [Date: 13-02-20] [Hit: ]
5 * a * t^2 = .5 * 4.9 * .71^2 = 1.......
(a) How far up the plane will it go? (b) How long until it returns to where it started from?

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I'm assuming g=9.8m/s^2
Also assuming no friction.

On a 30 degree incline, the component of the gravity vector parallel to the incline is g * sin(30), sin(30) = .5, so the acceleration is 4.9m^s^2

With an initial velocity of 3.5m/s, it will take 3.5/4.9 = .71 s to decelerate to stop, and another .71 s to accelerate and return back to the starting point. Total elapsed = 1.42 s (answer b)

The distance up the plane is computed from d = .5 * a * t^2 = .5 * 4.9 * .71^2 = 1.23m (answer a)
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