Tricky question :/ can you show your steps please?
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let your question be equal to some constant say 'I'
use the formula (which is taught to us dont know if you guys have the same) :
integral u(e^5x) . v (Sin12x) dx = u integral v dx - integral [ du/dx . integral v dx ] dx
use it twice , taking care of the ' minus (-) ' sign after using it twice you will get the question in your answer replace it I and take it to theother side to get '2I' one one side and get the answer in the form (which is a shorcut dont use it directed as its not allowed but just to verify your final answer)
integral e^ax . sinbx dx = e^ax/a^2 + b^2 [a sinbx-bcosbx]
it was lil complicated to answer your question as there are no such signs like 'integral'
hope i helped.
use the formula (which is taught to us dont know if you guys have the same) :
integral u(e^5x) . v (Sin12x) dx = u integral v dx - integral [ du/dx . integral v dx ] dx
use it twice , taking care of the ' minus (-) ' sign after using it twice you will get the question in your answer replace it I and take it to theother side to get '2I' one one side and get the answer in the form (which is a shorcut dont use it directed as its not allowed but just to verify your final answer)
integral e^ax . sinbx dx = e^ax/a^2 + b^2 [a sinbx-bcosbx]
it was lil complicated to answer your question as there are no such signs like 'integral'
hope i helped.
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1. Integrate it by parts so that you're taking the derivative of sin12x
2. You'll end up with another integral, this time with cos12x instead of sine
3. Integrate this by parts, taking the derivative of the trig function
4. You'll end up with the original integral again
5. Add this integral to the side with the integral you were trying to find. This way, you can solve for the integral itself without taking its antiderivative
2. You'll end up with another integral, this time with cos12x instead of sine
3. Integrate this by parts, taking the derivative of the trig function
4. You'll end up with the original integral again
5. Add this integral to the side with the integral you were trying to find. This way, you can solve for the integral itself without taking its antiderivative