how would you solve for the question,
use a substitution to integrate ∫ (2x-1)/(4x^2-4x)^2 dx
find the substitution u to transform the integral into 1/16∫ u^-2 du
use a substitution to integrate ∫ (2x-1)/(4x^2-4x)^2 dx
find the substitution u to transform the integral into 1/16∫ u^-2 du
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∫ (2x - 1) / (4x² - 4x)² dx
∫ (2x - 1) / (4² (x² - x)²) dx
1/16 ∫ (2x - 1) / (x² - x)² dx
Let u = x² - x
du = (2x - 1) dx
1/16 ∫ 1/u² du
∫ (2x - 1) / (4² (x² - x)²) dx
1/16 ∫ (2x - 1) / (x² - x)² dx
Let u = x² - x
du = (2x - 1) dx
1/16 ∫ 1/u² du