How to integrate (y-x)/(x+y)

the equation is:

dy/dx = (y-x)/(x+y)

how would i integrate this??

try with putting y=mx

=>dy/dx=(y-x)/(x+y)

=>d(mx)/dx={x(m-1)/x(1+m)}

=>m+xdm/dx=(m-1)/(m+1)

=>x*d(m)/dx=-(m^2+1)/(m+1)

=>(m+1)/(m^2+1)dm=-(1/x)dx

=>1/2*ln|m^2+1|+tan^-1(m)=-ln|x|+c

=>1/2ln|(y/x)^2+1|+tan^-(y/x)=-ln|x|+c

thanks.

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(y-x)/(x+y)
xy+y^2-x^2-xy
y^2-x^2

=y/3^3-x/3^3

if that makes any sense

basically just expand the brackets and then integrate. I don't know how to do all of the correct notation on a computer.