Finding the equation of a straight line (parallel)
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Finding the equation of a straight line (parallel)

[From: ] [author: ] [Date: 13-02-03] [Hit: ]
Please explain how to solve this. Thanks!Passes through (0, -10) and is parallel to the line with equation y=6x+3-Since the equation you have is written in slope-intercept form, y = slope (x) + y-intercept. 6 is the slope of the line and 3 is the y-intercept.......
Hi, I'm really confused with parallel lines, how do I find the equation of the straight line? Please explain how to solve this. Thanks!

Passes through (0, -10) and is parallel to the line with equation y=6x+3

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Since the equation you have is written in slope-intercept form, y = slope (x) + y-intercept. 6 is the slope of the line and 3 is the y-intercept. You want the line you draw to have a slope of 6 also because parallel lines have the same slope. In the point you have, (0, -10), -10 is the y-intercept because it is the "y" in the ordered pair (x,y). So, the equation of the line is y = 6x -10. Hope this helped!

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Parallel lines have the same slope. Perpendicular lines have opposite reciprocal slopes (m and -1/m). Easy enough right?
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