Maths equation prob help
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Maths equation prob help

[From: ] [author: ] [Date: 13-02-03] [Hit: ]
i.e.so,The height is 9 metres at times of 0.2 seconds and 2 seconds.:)>-(b) 2 seconds and 0.......
A bal was thrown vertically upwards so that its height h metres above the ground, t seconds after it had been thrown, was given by the formula.
h=7 + 11t - 5t^2

Find
(a)the height above the ground from which the was thrown.
(b)the two values of t for which the ball was 9 metres above the ground.

-
(a) The initial height is when t = 0.

=> h(0) = 7 metres

(b) We require when h(t) = 9

=> 7 + 11t - 5t² = 9

=> 5t² - 11t + 2 = 0

i.e. (5t - 1)(t - 2) = 0

so, t = 1/5 and t = 2

The height is 9 metres at times of 0.2 seconds and 2 seconds.

:)>

-
(b) 2 seconds and 0.20 second

-
a) 7 metres as h=7 when t=0
b) 9 = 7 + 11t - 5t^2 ie 5t^2 -11t +2 =0 ie (5t-1)(t-2)=0 ie t = 1/5sec or 2sec
1
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