A gaseous hydrocarbon composed of 80% carbon mass. Determine the empirical formula of the compound, if it's known that the compound mass of 1 liter (STP) is 1.34 grams! Determine the molecular formula too!
Please solve that question with the step. I'm very grateful by your help.
Please solve that question with the step. I'm very grateful by your help.
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1 mole of the gas occupies 22.4 liters
we have 1 liter of gas so we have 1 liter // 22.4 liters / mole = 0.04464 moles
these have mass of 1.34 g so molar mass = 1.34g / 0.04464 moles = 30.02 g / mol
the compound has 80% C = 80% of 30g = 24 g or 2 moles of C
these of 20 % of H = 20 % 0f 30g = 6 g or 6 moles of H
molecular formula is C2H6 ..
empirical formula is CH3
we have 1 liter of gas so we have 1 liter // 22.4 liters / mole = 0.04464 moles
these have mass of 1.34 g so molar mass = 1.34g / 0.04464 moles = 30.02 g / mol
the compound has 80% C = 80% of 30g = 24 g or 2 moles of C
these of 20 % of H = 20 % 0f 30g = 6 g or 6 moles of H
molecular formula is C2H6 ..
empirical formula is CH3