For this problem I am supposed to decide whether to integrate with respect to x or y but I'm sure which to choose. Then I need to find the area of the region.
y= e^(3x)
y=e^(8x)
x=1
Help would be greatly appreciated
y= e^(3x)
y=e^(8x)
x=1
Help would be greatly appreciated
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dx is a whole lot easier i think since everythings already written in terms of x
∫ e^(8x) - e^(3x) dx evaluated from 0 to 1
(1/8)e^(8x) - (1/3)e^(3x) } evaluate
((1/8)e^(8) - (1/3)e^(3)) - (1/8 - 1/3))
((1/8)e^(8) - (1/3)e^(3)) + 5/24
(3e^8 - 8e^3 + 5) / 24
∫ e^(8x) - e^(3x) dx evaluated from 0 to 1
(1/8)e^(8x) - (1/3)e^(3x) } evaluate
((1/8)e^(8) - (1/3)e^(3)) - (1/8 - 1/3))
((1/8)e^(8) - (1/3)e^(3)) + 5/24
(3e^8 - 8e^3 + 5) / 24
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fsad