A plane accelerates at 25 m/s^2 and takes 850m to lift off calculate its take off speed.

Whats the take off speed and how did you calculate it? thanks.

This is the general formula:

S = 1/2 a t^2 + Vo t

V = a t + Vo

where:
S: distance
a: acceleration
Vo: initial speed
t: time
V: final speed

In your case:
Known: a = 25 m/s^2, S = 850 m, Vo = 0 (no initial speed)
Asked: V

S = 1/2 a t^2 + Vo t
850 = 1/2 x 25 x t^2 + 0
850 = 12.5 t^2
t^2 = 68
t = 8.25 s


V = a t + Vo
= 25 x 8.25 + 0
= 206.25 m/s

Vto = √[2*a*x] = 206 m/s

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