How to solve hyperbola question
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How to solve hyperbola question

[From: ] [author: ] [Date: 13-02-16] [Hit: ]
-the foci at (0,6) and (0,-6)=> the center is (0,http://www.wolframalpha.com/input/?......
The hyperbola is equilateral and has foci at (0,6) and (0,-6). So far I found out that the center is (0,0) and C is 5. I need help finding the a squared and b squared in the problem so I can write the hyperbola equation.

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the foci at (0,6) and (0,-6) => the center is (0,0) and C is 6
The hyperbola is equilateral => a=b
c^2 = a^2+b^2
36 = 2a^2
a^2 = b^2 = 18
x^2/18 - y^2/18 = 1
http://www.wolframalpha.com/input/?i=x^2…
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