Using absolute value 3|y-1| - 12 =0 what is the solution set using set notation
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Using absolute value 3|y-1| - 12 =0 what is the solution set using set notation

[From: ] [author: ] [Date: 13-01-30] [Hit: ]
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Please

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3|y-1| = 12
|y-1| = 12/3
|y-1| = 4

y-1 = 4 or y-1 = -4
y = 5 or y = -3

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3y-3-12=0
3y-15=0
3y=15
3y/3=15/3
y=5
1
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