x^2+3x+6
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Equating this to zero and solving using quadratic formula (No knowledge on complex number method),
the solution is:
x = [-3 ± √(3² - 24)]/2 = [-3 ± √-15]/2 = (-3 ± √15*i)/2 = (-3/2) ± (√15/2)*i
Thus the solution is: = {(-3 + √15i)/2, (-3-√15i)/2}
the solution is:
x = [-3 ± √(3² - 24)]/2 = [-3 ± √-15]/2 = (-3 ± √15*i)/2 = (-3/2) ± (√15/2)*i
Thus the solution is: = {(-3 + √15i)/2, (-3-√15i)/2}
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Set it equal to 0.