How do I do the rest of this question to get the eqt of the tangent

so I am getting this wrong... and I don't know how to do half the problem so please help me.

Find the equation of the tangent to each of the following curves at the point corresponding to the given x value

y = tanx where x = pi divided by 4
I got the gradient and m was equal to 2

but now I'm not sure... I went y = x + c
sub point (pi divided by four, 0) then got c as minues pi divided by 4 and then y = 2x - pi divided by four

the answer was y = 2x - pi divided by 2 + 1

how do I get that??

thankyou very much

y = tanx

y' = sec^2(x)

y'(π/4) = sec^2(π/4)

y'(π/4) = 2

Use point slope form:
Where the point given is:
x = π/4
y = tan(π/4) = 1

(y-1) = 2(x - π/4)

y = 2x - π/2 + 1