Determine the limit by substitution. Support graphically.

lim (y approaches 2) y^2 + 5y + 6/ (y+2)
I'm confused.
If you plug in for y = 2 the denominator the denominator is zero which is undefined.
If you try factoring the denominator is still zero
And if your try multiplying by the conjugate the denominator is still zero.

How do you solve this?

Pretty sure you typed it in wrong.

Direct substitution will work:
(4 + 10 + 6) / (4)

20/4 = 5

Factoring and canceling will work:
(y+3)(y+2) / (y+2)

(y+3)

lim y-->2 (y+3) = 5

So idk what the dilemma is.....?