10 pointsShifting Quadratic Graphs

-x(x-4) archway (metres)

vertex of the first archway is moved 4 metres right and 1 meter up. The new archway is the same height as the first archway "-x(x-4)" but only half as wide at the bottom

-4(x-6)^2+5 proper answer or is it wrong ,
idk check pls

y = -x(x- 4) = -x^2 + 4x
y = -(x - 2)^2 + 4

we move this 4 metres right:

y = -(x - 6)^2 + 4

now move 1 metre up:

y = -(x - 6)^2 + 5

make 1/2 as wide:

y = -(2(x - 6))^2 + 5
y = -4(x - 6)^2 + 5